[unix] 비디오 파일에서 이미지를 추출하는 방법?

이 도움을 바랍니다

#!/bin/bash
source_dir="."
output_dir="."
input_file_types=(avi wmv flv mkv mpg mp4)
output_file_type="jpg"

convert() {
        echo "" | ffmpeg -ss $ss -y -i "$in_file" -an -f image2 -vframes 1 "$output_dir/$out_file"
}

for input_file_types in "${input_file_types[@]}"
do

        find "$source_dir" -name "*.$input_file_types" -print0 | while IFS= read -r -d $'\0' in_file
        do
                echo "Processing…"
                echo ">Input  "$in_file
                # Replace the file type
                out_file=$(echo $in_file|sed "s/\(.*\.\)$input_file_types/\1$output_file_type/g")
            echo ">Output "$out_file

# get video duration
#    fulltime=`ffmpeg -i "$in_file" 2>&1 | grep 'Duration' | cut -d ' ' -f 4 | sed s/,//`;
#    hour=`echo $fulltime | cut -d ':' -f 1`;
#    minute=`echo $fulltime | cut -d ':' -f 2`;
#    second=`echo $fulltime | cut -d ':' -f 3 | cut -d '.' -f 1`;

#    seconds=`expr 3600 \* $hour + 60 \* $minute + $second`;
#    ss=`expr $seconds / 2`; # from the middle of video



    ss=`expr 10`; # from the 10sec of video



    # Convert the file
                convert "$in_file" "$out_file"

                if [ $? != 0 ]
                then
                    echo "$in_file had problems" >> ffmpeg-errors.log
                fi

                echo ">Finished "$out_file "\n\n"
        done
done

답변