SQL Server 2005+의 모든 인덱스 및 인덱스 열 목록을 어떻게 얻습니까? 내가 얻을 수있는 가장 가까운 것은 다음과 같습니다.
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
order by ic.key_ordinal정확히 내가 원하는 것이 아닙니다.
내가 원하는 것은 모든 사용자 정의 인덱스 ( 기본 제약 조건 및 기본 키를 지원하는 인덱스가 없음 )를 모든 열 (인덱스 정의에 표시되는 방식으로 정렬)과 가능한 한 많은 메타 데이터로 나열하는 것입니다.
답변
참조 할 수있는 “sys”카탈로그 뷰는 두 가지입니다.
select * from sys.indexesselect * from sys.index_columns그것들은 인덱스와 컬럼에 대해 원하는 정보를 제공합니다.
편집 :이 쿼리는 당신이 찾고있는 것에 아주 가까워지고 있습니다 :
SELECT
TableName = t.name,
IndexName = ind.name,
IndexId = ind.index_id,
ColumnId = ic.index_column_id,
ColumnName = col.name,
ind.*,
ic.*,
col.*
FROM
sys.indexes ind
INNER JOIN
sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id
INNER JOIN
sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN
sys.tables t ON ind.object_id = t.object_id
WHERE
ind.is_primary_key = 0
AND ind.is_unique = 0
AND ind.is_unique_constraint = 0
AND t.is_ms_shipped = 0
ORDER BY
t.name, ind.name, ind.index_id, ic.index_column_id;답변
를 사용하여 sp_helpindex한 테이블의 모든 인덱스를 볼 수 있습니다 .
EXEC sys.sp_helpindex @objname = N'User' -- nvarchar(77)그리고 모든 sys.objects인덱스에 대해 각 테이블에 대한 모든 인덱스를 가져 오기 위해 순회 할 수 있습니다 .
답변
위의 어느 것도 나를 위해 일하지 않았지만 이것은 다음과 같습니다.
-- KDF9's concise index list for SQL Server 2005+ (see below for 2000)
-- includes schemas and primary keys, in easy to read format
-- with unique, clustered, and all ascending/descendings in a single column
-- Needs simple manual add or delete to change maximum number of key columns
-- but is easy to understand and modify, with no UDFs or complex logic
--
SELECT
schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName,
(CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK,
(CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+
(CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' '+ -- B=basic, C=Clustered, X=XML
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,1,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,2,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,3,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,4,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,5,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,6,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
'' as 'Type',
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,1) as Key1,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,2) as Key2,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,3) as Key3,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,4) as Key4,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,5) as Key5,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,6) as Key6
FROM sys.indexes as si
LEFT JOIN sys.objects as so on so.object_id=si.object_id
WHERE index_id>0 -- omit the default heap
and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables
and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams
ORDER BY SchemaName,TableName,IndexName
-------------------------------------------------------------------
-- or to generate creation scripts put a simple wrapper around that
SELECT SchemaName, TableName, IndexName,
(CASE pk
WHEN 'PK' THEN 'ALTER '+
'TABLE '+SchemaName+'.'+TableName+' ADD CONSTRAINT '+IndexName+' PRIMARY KEY'+
(CASE substring(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END)
ELSE 'CREATE '+
(CASE substring(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+
(CASE substring(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+
'INDEX '+IndexName+' ON '+SchemaName+'.'+TableName
END)+
' ('+
(CASE WHEN Key1 is null THEN '' ELSE Key1+(CASE substring(Type,4+1,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key2 is null THEN '' ELSE ', '+Key2+(CASE substring(Type,4+2,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key3 is null THEN '' ELSE ', '+Key3+(CASE substring(Type,4+3,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key4 is null THEN '' ELSE ', '+Key4+(CASE substring(Type,4+4,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key5 is null THEN '' ELSE ', '+Key5+(CASE substring(Type,4+5,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key6 is null THEN '' ELSE ', '+Key6+(CASE substring(Type,4+6,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
')' as CreateIndex
FROM (
...
...listing SQL same as above minus the ORDER BY...
...
) as indexes
ORDER BY SchemaName,TableName,IndexName
----------------------------------------------------------
-- For SQL Server 2000 the following should work
-- change table names to sysindexes and sysobjects (no dots)
-- change object_id => id, index_id => indid,
-- change is_primary_key => (select count(constid) from sysconstraints as sc where sc.id=si.id and sc.status&15=1)
-- change is_unique => INDEXPROPERTY(si.id,si.name,'IsUnique')
-- change si.type => INDEXPROPERTY(si.id,si.name,'IsClustered')
-- remove all references to schemas including schema name qualifiers, and the XML type
-- add select where indid<255 and si.status&64=0 (to omit the text/image index and autostats)이름에 공백이 포함 된 경우 작성 스크립트에서 공백을 대괄호로 묶으십시오.
마지막 키 열이 모두 널이면 누락 된 것이 없음을 알 수 있습니다.
원래 요청에서와 같이 기본 키 등을 걸러내는 것은 쉽지 않습니다.
참고 :이 솔루션은 인덱스 열과 포함 열을 구분하지 않으므로주의하십시오.
답변
–짧고 달다:
SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema],
T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name],
I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key],
I.[is_unique_constraint], I.[fill_factor], I.[is_padded], I.[is_disabled], I.[is_hypothetical],
I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column]
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id]
INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id]
WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP'
ORDER BY T.[name], I.[index_id], IC.[key_ordinal] 답변
다음은 SQL Server 2014/2016 및 모든 Microsoft Azure SQL 데이터베이스에서 작동합니다.
슬라이싱 및 다이 싱을 위해 메모장 / 엑셀로 쉽게 내보낼 수있는 포괄적 인 결과 집합을 생성합니다.
- 테이블 이름
- 색인 이름
- 색인 설명
- 인덱싱 된 열-순서대로
- 포함 된 열-순서대로
SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name'
,+ i.NAME AS 'index_name'
,LOWER(i.type_desc) + CASE
WHEN i.is_unique = 1
THEN ', unique'
ELSE ''
END + CASE
WHEN i.is_primary_key = 1
THEN ', primary key'
ELSE ''
END AS 'index_description'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 0
ORDER BY key_ordinal
FOR XML PATH('')
), 1, 2, '') AS 'indexed_columns'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 1
FOR XML PATH('')
), 1, 2, '') AS 'included_columns'
FROM sysindexes AS i1
INNER JOIN sys.indexes AS i ON i.object_id = i1.id
AND i.index_id = i1.indid
INNER JOIN sysobjects AS o ON o.id = i1.id
INNER JOIN sys.objects AS so ON so.object_id = o.id
AND is_ms_shipped = 0
INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id
WHERE so.type = 'U'
AND i1.indid < 255
AND i1.STATUS & 64 = 0 --index with duplicates
AND i1.STATUS & 8388608 = 0 --auto created index
AND i1.STATUS & 16777216 = 0 --stats no recompute
AND i.type_desc <> 'heap'
AND so.NAME <> 'sysdiagrams'
ORDER BY table_name
,index_name;답변
안녕하세요, 저는 통과하지 않았지만 원저자가 게시 한 쿼리에서 원하는 것을 얻었습니다.
요구 사항에 조건 (필터없이)을 사용했지만 잘못된 결과를 얻었습니다.
주요 문제는 index_id에서 조인 조건없이 교차 제품을 얻는 결과 였습니다.
SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME
FROM SYS.TABLES T
INNER JOIN SYS.SCHEMAS S
ON T.SCHEMA_ID = S.SCHEMA_ID
INNER JOIN SYS.INDEXES I
ON I.OBJECT_ID = T.OBJECT_ID
INNER JOIN SYS.INDEX_COLUMNS IC
ON IC.OBJECT_ID = T.OBJECT_ID
INNER JOIN SYS.COLUMNS C
ON C.OBJECT_ID = T.OBJECT_ID
**AND IC.INDEX_ID = I.INDEX_ID**
AND IC.COLUMN_ID = C.COLUMN_ID
WHERE 1=1
ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL답변
특정 인덱스, 인덱스 열 및 포함 된 열도 가져와야했습니다. 내가 사용한 쿼리는 다음과 같습니다.
SELECT INX.[name] AS [Index Name]
,TBL.[name] AS [Table Name]
,DS1.[IndexColumnsNames]
,DS2.[IncludedColumnsNames]
FROM [sys].[indexes] INX
INNER JOIN [sys].[tables] TBL
ON INX.[object_id] = TBL.[object_id]
CROSS APPLY
(
SELECT STUFF
(
(
SELECT ' [' + CLS.[name] + ']'
FROM [sys].[index_columns] INXCLS
INNER JOIN [sys].[columns] CLS
ON INXCLS.[object_id] = CLS.[object_id]
AND INXCLS.[column_id] = CLS.[column_id]
WHERE INX.[object_id] = INXCLS.[object_id]
AND INX.[index_id] = INXCLS.[index_id]
AND INXCLS.[is_included_column] = 0
FOR XML PATH('')
)
,1
,1
,''
)
) DS1 ([IndexColumnsNames])
CROSS APPLY
(
SELECT STUFF
(
(
SELECT ' [' + CLS.[name] + ']'
FROM [sys].[index_columns] INXCLS
INNER JOIN [sys].[columns] CLS
ON INXCLS.[object_id] = CLS.[object_id]
AND INXCLS.[column_id] = CLS.[column_id]
WHERE INX.[object_id] = INXCLS.[object_id]
AND INX.[index_id] = INXCLS.[index_id]
AND INXCLS.[is_included_column] = 1
FOR XML PATH('')
)
,1
,1
,''
)
) DS2 ([IncludedColumnsNames])