[java] Java에서 URL에 대한 HTTP 응답 코드를 얻는 방법은 무엇입니까?

JAVA / 글쓴이

특정 URL의 응답 코드를 얻는 단계 또는 코드를 알려주십시오.

답변

HttpURLConnection :

URL url = new URL("http://example.com");
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("GET");
connection.connect();

int code = connection.getResponseCode();

이것은 결코 강력한 예가 아닙니다. 를 처리해야합니다 IOException. 하지만 시작해야합니다.

더 많은 기능이 필요한 것이 있으면 HttpClient를 확인하십시오 .

답변

URL url = new URL("http://www.google.com/humans.txt");
HttpURLConnection http = (HttpURLConnection)url.openConnection();
int statusCode = http.getResponseCode();

답변

다음을 시도해 볼 수 있습니다. 

class ResponseCodeCheck
{

    public static void main (String args[]) throws Exception
    {

        URL url = new URL("http://google.com");
        HttpURLConnection connection = (HttpURLConnection)url.openConnection();
        connection.setRequestMethod("GET");
        connection.connect();

        int code = connection.getResponseCode();
        System.out.println("Response code of the object is "+code);
        if (code==200)
        {
            System.out.println("OK");
        }
    }
}

답변

import java.io.IOException;
import java.net.URL;
import java.net.HttpURLConnection;

public class API{
    public static void main(String args[]) throws IOException
    {
        URL url = new URL("http://www.google.com");
        HttpURLConnection http = (HttpURLConnection)url.openConnection();
        int statusCode = http.getResponseCode();
        System.out.println(statusCode);
    }
}

답변

이것은 나를 위해 일했다 :

            import org.apache.http.client.HttpClient;
            import org.apache.http.client.methods.HttpGet;
            import org.apache.http.impl.client.DefaultHttpClient;
            import org.apache.http.HttpResponse;
            import java.io.BufferedReader;
            import java.io.InputStreamReader;



            public static void main(String[] args) throws Exception {
                        HttpClient client = new DefaultHttpClient();
                        //args[0] ="http://hostname:port/xyz/zbc";
                        HttpGet request1 = new HttpGet(args[0]);
                        HttpResponse response1 = client.execute(request1);
                        int code = response1.getStatusLine().getStatusCode();

                         try(BufferedReader br = new BufferedReader(new InputStreamReader((response1.getEntity().getContent())));){
                            // Read in all of the post results into a String.
                            String output = "";
                            Boolean keepGoing = true;
                            while (keepGoing) {
                                String currentLine = br.readLine();
                                if (currentLine == null) {
                                    keepGoing = false;
                                } else {
                                    output += currentLine;
                                }
                            }
                            System.out.println("Response-->"+output);
                         }

                         catch(Exception e){
                              System.out.println("Exception"+e);

                          }


                   }

답변

이것이 나를 위해 일한 것입니다.

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.URL;

public class UrlHelpers {

    public static int getHTTPResponseStatusCode(String u) throws IOException {

        URL url = new URL(u);
        HttpURLConnection http = (HttpURLConnection)url.openConnection();
        return http.getResponseCode();
    }
}

희망이 누군가에게 도움이되기를 바랍니다 🙂

답변

400 오류 메시지를 확인하는이 코드 조각을 사용해보십시오

huc = (HttpURLConnection)(new URL(url).openConnection());

huc.setRequestMethod("HEAD");

huc.connect();

respCode = huc.getResponseCode();

if(respCode >= 400) {
    System.out.println(url+" is a broken link");
} else {
    System.out.println(url+" is a valid link");
}