현재 날짜 NSDate()와 PHP time();호출 날짜 의 차이를 얻으려고합니다 ( 예 🙂 NSDate(timeIntervalSinceReferenceDate: 1417147270). 두 날짜 사이의 시간 차이를 얻는 방법은 무엇입니까? 두 날짜를 비교 if(seconds > 60)한 다음 분, if(minutes > 60)반환 시간 및 if(hours > 24)반환 일 등을 반환 하는 함수를 갖고 싶습니다 .
어떻게해야합니까?
편집 : 현재 받아 들여지는 대답은 내가하고 싶은 일을 정확하게 수행했습니다. PHP time()함수가 사용 하는 형식으로 두 날짜 사이의 시간을 얻는 데 사용하기 쉽도록 권장 합니다. PHP에 익숙하지 않다면 1970 년 1 월 1 일부터 몇 초가 지나야합니다. 이는 PHP의 백엔드에 유용합니다. NodeJS와 같은 백엔드를 사용하는 경우 아래에서 찾을 수있는 다른 옵션 중 일부를 고려할 수 있습니다.
답변
Xcode 8.3 • Swift 3.1 이상
캘린더를 사용하여 다음과 같이 날짜 계산을 수행하는 확장을 만들 수 있습니다.
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfMonth], from: date, to: self).weekOfMonth ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
}
날짜 구성 요소 포맷터 사용
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
dateComponentsFormatter.maximumUnitCount = 1
dateComponentsFormatter.unitsStyle = .full
dateComponentsFormatter.string(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
let date1 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date2 = DateComponents(calendar: .current, year: 2015, month: 8, day: 28, hour: 5, minute: 9).date!
let years = date2.years(from: date1) // 0
let months = date2.months(from: date1) // 9
let weeks = date2.weeks(from: date1) // 39
let days = date2.days(from: date1) // 273
let hours = date2.hours(from: date1) // 6,553
let minutes = date2.minutes(from: date1) // 393,180
let seconds = date2.seconds(from: date1) // 23,590,800
let timeOffset = date2.offset(from: date1) // "9M"
let date3 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date4 = DateComponents(calendar: .current, year: 2015, month: 11, day: 28, hour: 5, minute: 9).date!
let timeOffset2 = date4.offset(from: date3) // "1y"
let date5 = DateComponents(calendar: .current, year: 2017, month: 4, day: 28).date!
let now = Date()
let timeOffset3 = now.offset(from: date5) // "1w"
답변
누군가가 “시간”뿐만 아니라 “시간 분 초”와 같은 모든 시간 단위를 표시해야하는 경우. 두 날짜의 시차가 1 시간 59 분 20 초라고 가정 해 봅시다. 이 기능은 “1h 59m 20s”를 표시합니다.
내 Objective-C 코드는 다음과 같습니다.
extension NSDate {
func offsetFrom(date: NSDate) -> String {
let dayHourMinuteSecond: NSCalendarUnit = [.Day, .Hour, .Minute, .Second]
let difference = NSCalendar.currentCalendar().components(dayHourMinuteSecond, fromDate: date, toDate: self, options: [])
let seconds = "\(difference.second)s"
let minutes = "\(difference.minute)m" + " " + seconds
let hours = "\(difference.hour)h" + " " + minutes
let days = "\(difference.day)d" + " " + hours
if difference.day > 0 { return days }
if difference.hour > 0 { return hours }
if difference.minute > 0 { return minutes }
if difference.second > 0 { return seconds }
return ""
}
}
스위프트 3 이상에서 :
extension Date {
func offsetFrom(date: Date) -> String {
let dayHourMinuteSecond: Set<Calendar.Component> = [.day, .hour, .minute, .second]
let difference = NSCalendar.current.dateComponents(dayHourMinuteSecond, from: date, to: self)
let seconds = "\(difference.second ?? 0)s"
let minutes = "\(difference.minute ?? 0)m" + " " + seconds
let hours = "\(difference.hour ?? 0)h" + " " + minutes
let days = "\(difference.day ?? 0)d" + " " + hours
if let day = difference.day, day > 0 { return days }
if let hour = difference.hour, hour > 0 { return hours }
if let minute = difference.minute, minute > 0 { return minutes }
if let second = difference.second, second > 0 { return seconds }
return ""
}
}
답변
물어:
두 날짜와 if (seconds> 60)를 비교하고 분, if (minutes> 60) 반환 시간 및 if (hours> 24) 반환 일 등을 비교하는 함수를 갖고 싶습니다.
두 날짜 사이의 경과 시간을 문자열로 표시하려고한다고 가정합니다. Apple은 자신의 코드를 작성하는 대신 이미 그렇게하는 클래스를 가지고 있습니다. 즉,을 사용 DateComponentsFormatter하고 allowedUnits앱에 적합한 값으로 설정 하고 원하는 값 unitsStyle(예 :)으로 설정 .full한 다음을 호출하십시오 string(from:to:).
예 : 스위프트 3
let previousDate = ...
let now = Date()
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [.month, .day, .hour, .minute, .second]
formatter.maximumUnitCount = 2 // often, you don't care about seconds if the elapsed time is in months, so you'll set max unit to whatever is appropriate in your case
let string = formatter.string(from: previousDate, to: now)
또한 해당 장치에 적합한 문자열을 현지화합니다.
또는 Swift 2.3에서 :
let previousDate = ...
let now = NSDate()
let formatter = NSDateComponentsFormatter()
formatter.unitsStyle = .Full
formatter.allowedUnits = [.Month, .Day, .Hour, .Minute, .Second]
formatter.maximumUnitCount = 2
let string = formatter.stringFromDate(previousDate, toDate: now)
실제 숫자 값을 찾으려면을 사용하십시오 dateComponents. 예 : 스위프트 3
let components = Calendar.current.dateComponents([.month, .day, .hour, .minute, .second], from: previousDate, to: now)또는 Swift 2.3에서 :
let components = NSCalendar.currentCalendar().components([.Month, .Day, .Hour, .Minute, .Second], fromDate: previousDate, toDate: now, options: [])답변
@ leo-dabus의 답변에서 결합 된 Extension + DateComponentsFormatter
Xcode 8.3 • 스위프트 3.1
extension DateComponentsFormatter {
func difference(from fromDate: Date, to toDate: Date) -> String? {
self.allowedUnits = [.year,.month,.weekOfMonth,.day]
self.maximumUnitCount = 1
self.unitsStyle = .full
return self.string(from: fromDate, to: toDate)
}
}
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.difference(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
답변
func dateDiff(dateStr:String) -> String {
var f:NSDateFormatter = NSDateFormatter()
f.timeZone = NSTimeZone.localTimeZone()
f.dateFormat = "yyyy-M-dd'T'HH:mm:ss.SSSZZZ"
var now = f.stringFromDate(NSDate())
var startDate = f.dateFromString(dateStr)
var endDate = f.dateFromString(now)
var calendar: NSCalendar = NSCalendar.currentCalendar()
let calendarUnits = NSCalendarUnit.CalendarUnitWeekOfMonth | NSCalendarUnit.CalendarUnitDay | NSCalendarUnit.CalendarUnitHour | NSCalendarUnit.CalendarUnitMinute | NSCalendarUnit.CalendarUnitSecond
let dateComponents = calendar.components(calendarUnits, fromDate: startDate!, toDate: endDate!, options: nil)
let weeks = abs(dateComponents.weekOfMonth)
let days = abs(dateComponents.day)
let hours = abs(dateComponents.hour)
let min = abs(dateComponents.minute)
let sec = abs(dateComponents.second)
var timeAgo = ""
if (sec > 0){
if (sec > 1) {
timeAgo = "\(sec) Seconds Ago"
} else {
timeAgo = "\(sec) Second Ago"
}
}
if (min > 0){
if (min > 1) {
timeAgo = "\(min) Minutes Ago"
} else {
timeAgo = "\(min) Minute Ago"
}
}
if(hours > 0){
if (hours > 1) {
timeAgo = "\(hours) Hours Ago"
} else {
timeAgo = "\(hours) Hour Ago"
}
}
if (days > 0) {
if (days > 1) {
timeAgo = "\(days) Days Ago"
} else {
timeAgo = "\(days) Day Ago"
}
}
if(weeks > 0){
if (weeks > 1) {
timeAgo = "\(weeks) Weeks Ago"
} else {
timeAgo = "\(weeks) Week Ago"
}
}
print("timeAgo is===> \(timeAgo)")
return timeAgo;
}
답변
“2w”대신 “2 주 전”과 같은 문자열을 원할 경우를 대비하여 Leo Dabus ‘s asnwer에 “long”버전을 추가했습니다.
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfYear], from: date, to: self).weekOfYear ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
func offsetLong(from date: Date) -> String {
if years(from: date) > 0 { return years(from: date) > 1 ? "\(years(from: date)) years ago" : "\(years(from: date)) year ago" }
if months(from: date) > 0 { return months(from: date) > 1 ? "\(months(from: date)) months ago" : "\(months(from: date)) month ago" }
if weeks(from: date) > 0 { return weeks(from: date) > 1 ? "\(weeks(from: date)) weeks ago" : "\(weeks(from: date)) week ago" }
if days(from: date) > 0 { return days(from: date) > 1 ? "\(days(from: date)) days ago" : "\(days(from: date)) day ago" }
if hours(from: date) > 0 { return hours(from: date) > 1 ? "\(hours(from: date)) hours ago" : "\(hours(from: date)) hour ago" }
if minutes(from: date) > 0 { return minutes(from: date) > 1 ? "\(minutes(from: date)) minutes ago" : "\(minutes(from: date)) minute ago" }
if seconds(from: date) > 0 { return seconds(from: date) > 1 ? "\(seconds(from: date)) seconds ago" : "\(seconds(from: date)) second ago" }
return ""
}
}
답변
-> 이것을 사용하여 Swift 에서 두 날짜 사이의 시간 간격을 찾으십시오 (두 문자열 포함).
func timeGapBetweenDates(previousDate : String,currentDate : String)
{
let dateString1 = previousDate
let dateString2 = currentDate
let Dateformatter = DateFormatter()
Dateformatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let date1 = Dateformatter.date(from: dateString1)
let date2 = Dateformatter.date(from: dateString2)
let distanceBetweenDates: TimeInterval? = date2?.timeIntervalSince(date1!)
let secondsInAnHour: Double = 3600
let minsInAnHour: Double = 60
let secondsInDays: Double = 86400
let secondsInWeek: Double = 604800
let secondsInMonths : Double = 2592000
let secondsInYears : Double = 31104000
let minBetweenDates = Int((distanceBetweenDates! / minsInAnHour))
let hoursBetweenDates = Int((distanceBetweenDates! / secondsInAnHour))
let daysBetweenDates = Int((distanceBetweenDates! / secondsInDays))
let weekBetweenDates = Int((distanceBetweenDates! / secondsInWeek))
let monthsbetweenDates = Int((distanceBetweenDates! / secondsInMonths))
let yearbetweenDates = Int((distanceBetweenDates! / secondsInYears))
let secbetweenDates = Int(distanceBetweenDates!)
if yearbetweenDates > 0
{
print(yearbetweenDates,"years")//0 years
}
else if monthsbetweenDates > 0
{
print(monthsbetweenDates,"months")//0 months
}
else if weekBetweenDates > 0
{
print(weekBetweenDates,"weeks")//0 weeks
}
else if daysBetweenDates > 0
{
print(daysBetweenDates,"days")//5 days
}
else if hoursBetweenDates > 0
{
print(hoursBetweenDates,"hours")//120 hours
}
else if minBetweenDates > 0
{
print(minBetweenDates,"minutes")//7200 minutes
}
else if secbetweenDates > 0
{
print(secbetweenDates,"seconds")//seconds
}
}
