[digital-signature] 공개 키는 서명을 어떻게 확인합니까?

키는 반대로 작동합니다.

공개 키 암호화, 개인 키 해독 (암호화) :

openssl rsautl -encrypt -inkey public.pem -pubin -in message.txt -out message.ssl
openssl rsautl -decrypt -inkey private.pem       -in message.ssl -out message.txt

개인 키 암호화, 공개 키 해독 (서명) :

openssl rsautl -sign -inkey private.pem       -in message.txt -out message.ssl
openssl rsautl       -inkey public.pem -pubin -in message.ssl -out message.txt

다음은이 전체 흐름을 테스트하는 예제 스크립트입니다 openssl.

#!/bin/sh
# Create message to be encrypted
echo "Creating message file"
echo "---------------------"
echo "My secret message" > message.txt
echo "done\n"

# Create asymmetric keypair
echo "Creating asymmetric key pair"
echo "----------------------------"
openssl genrsa -out private.pem 1024
openssl rsa -in private.pem -out public.pem -pubout
echo "done\n"

# Encrypt with public & decrypt with private
echo "Public key encrypts and private key decrypts"
echo "--------------------------------------------"
openssl rsautl -encrypt -inkey public.pem -pubin -in message.txt         -out message_enc_pub.ssl
openssl rsautl -decrypt -inkey private.pem       -in message_enc_pub.ssl -out message_pub.txt
xxd message_enc_pub.ssl # Print the binary contents of the encrypted message
cat message_pub.txt # Print the decrypted message
echo "done\n"

# Encrypt with private & decrypt with public
echo "Private key encrypts and public key decrypts"
echo "--------------------------------------------"
openssl rsautl -sign    -inkey private.pem -in message.txt          -out message_enc_priv.ssl
openssl rsautl -inkey public.pem -pubin    -in message_enc_priv.ssl -out message_priv.txt
xxd message_enc_priv.ssl
cat message_priv.txt
echo "done\n"

이 스크립트는 다음을 출력합니다.

Creating message file
---------------------
done

Creating asymmetric key pair
----------------------------
Generating RSA private key, 1024 bit long modulus
...........++++++
....++++++
e is 65537 (0x10001)
writing RSA key
done

Public key encrypts and private key decrypts
--------------------------------------------
00000000: 31c0 f70d 7ed2 088d 9675 801c fb9b 4f95  1...~....u....O.
00000010: c936 8cd0 0cc4 9159 33c4 9625 d752 5b77  .6.....Y3..%.R[w
00000020: 5bfc 988d 19fe d790 b633 191f 50cf 1bf7  [........3..P...
00000030: 34c0 7788 efa2 4967 848f 99e2 a442 91b9  4.w...Ig.....B..
00000040: 5fc7 6c79 40ea d0bc 6cd4 3c9a 488e 9913  _.ly@...l.<.H...
00000050: 387f f7d6 b8e6 5eba 0771 371c c4f0 8c7f  8.....^..q7.....
00000060: 8c87 39a9 0c4c 22ab 13ed c117 c718 92e6  ..9..L".........
00000070: 3d5b 8534 7187 cc2d 2f94 0743 1fcb d890  =[.4q..-/..C....
My secret message
done

Private key encrypts and public key decrypts
--------------------------------------------
00000000: 6955 cdd0 66e4 3696 76e1 a328 ac67 4ca3  iU..f.6.v..(.gL.
00000010: d6bb 5896 b6fe 68f1 55f1 437a 831c fee9  ..X...h.U.Cz....
00000020: 133a a7e9 005b 3fc5 88f7 5210 cdbb 2cba  .:...[?...R...,.
00000030: 29f1 d52d 3131 a88b 78e5 333e 90cf 3531  )..-11..x.3>..51
00000040: 08c3 3df8 b76e 41f2 a84a c7fb 0c5b c3b2  ..=..nA..J...[..
00000050: 9d3b ed4a b6ad 89bc 9ebc 9154 da48 6f2d  .;.J.......T.Ho-
00000060: 5d8e b686 635f b6a4 8774 a621 5558 7172  ]...c_...t.!UXqr
00000070: fbd3 0c35 df0f 6a16 aa84 f5da 5d5e 5336  ...5..j.....]^S6
My secret message
done

답변

var msg = 'secret message';

var encryptedMessage = encrypt(pub_key, msg);

var decryptedMessage = decrypt(priv_key, encryptedMessage);

print(msg == decryptedMessage == 'secret message'); // True

var msg = 'secret message';

var encryptedMessage = encrypt(priv_key, msg);

var decryptedMessage = decrypt(pub_key, encryptedMessage); // HOW DOES THIS WORK???

print(msg == decryptedMessage == 'secret message'); // True

E.g., `d = (p-1)(q-1); d * e = 1` (d is the inverse of e - public key)