Google AJAX 검색 API에서 일부 JSON 데이터를 구문 분석하려고합니다. 내가 가진 이 URL을 나는 결과가 표시되도록 그것을 분해하고 싶습니다. 현재이 코드를 작성했지만 단순화 된 JSON 문자열이있는 많은 예제가 있지만 다음에 수행 할 작업과 관련하여 꽤 길을 잃었습니다.
일반적으로 C # 및 .NET에 익숙하지 않기 때문에 ASP.NET 페이지에 대한 실제 텍스트 출력을 얻는 데 어려움을 겪었으므로 JSON.NET을 사용해 보는 것이 좋습니다. 누구나 Google AJAX 검색 API에서 JSON으로 가져 와서 화면에 인쇄하는 코드를 작성하는 올바른 방향으로 나를 가리킬 수 있습니까?
편집 : 모든 수정 ! 모든 결과가 정상적으로 작동합니다. 다시 한번 감사합니다 Dreas Grech!
using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.ServiceModel.Web;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
using System.IO;
using System.Text;
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
GoogleSearchResults g1 = new GoogleSearchResults();
const string json = @"{""responseData"": {""results"":[{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.cheese.com/"",""url"":""http://www.cheese.com/"",""visibleUrl"":""www.cheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:bkg1gwNt8u4J:www.cheese.com"",""title"":""\u003cb\u003eCHEESE\u003c/b\u003e.COM - All about \u003cb\u003echeese\u003c/b\u003e!."",""titleNoFormatting"":""CHEESE.COM - All about cheese!."",""content"":""\u003cb\u003eCheese\u003c/b\u003e - everything you want to know about it. Search \u003cb\u003echeese\u003c/b\u003e by name, by types of milk, by textures and by countries.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://en.wikipedia.org/wiki/Cheese"",""url"":""http://en.wikipedia.org/wiki/Cheese"",""visibleUrl"":""en.wikipedia.org"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:n9icdgMlCXIJ:en.wikipedia.org"",""title"":""\u003cb\u003eCheese\u003c/b\u003e - Wikipedia, the free encyclopedia"",""titleNoFormatting"":""Cheese - Wikipedia, the free encyclopedia"",""content"":""\u003cb\u003eCheese\u003c/b\u003e is a food consisting of proteins and fat from milk, usually the milk of cows, buffalo, goats, or sheep. It is produced by coagulation of the milk \u003cb\u003e...\u003c/b\u003e""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.ilovecheese.com/"",""url"":""http://www.ilovecheese.com/"",""visibleUrl"":""www.ilovecheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:GBhRR8ytMhQJ:www.ilovecheese.com"",""title"":""I Love \u003cb\u003eCheese\u003c/b\u003e!, Homepage"",""titleNoFormatting"":""I Love Cheese!, Homepage"",""content"":""The American Dairy Association\u0026#39;s official site includes recipes and information on nutrition and storage of \u003cb\u003echeese\u003c/b\u003e.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.gnome.org/projects/cheese/"",""url"":""http://www.gnome.org/projects/cheese/"",""visibleUrl"":""www.gnome.org"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:jvfWnVcSFeQJ:www.gnome.org"",""title"":""\u003cb\u003eCheese\u003c/b\u003e"",""titleNoFormatting"":""Cheese"",""content"":""\u003cb\u003eCheese\u003c/b\u003e uses your webcam to take photos and videos, applies fancy special effects and lets you share the fun with others. It was written as part of Google\u0026#39;s \u003cb\u003e...\u003c/b\u003e""}],""cursor"":{""pages"":[{""start"":""0"",""label"":1},{""start"":""4"",""label"":2},{""start"":""8"",""label"":3},{""start"":""12"",""label"":4},{""start"":""16"",""label"":5},{""start"":""20"",""label"":6},{""start"":""24"",""label"":7},{""start"":""28"",""label"":8}],""estimatedResultCount"":""14400000"",""currentPageIndex"":0,""moreResultsUrl"":""http://www.google.com/search?oe\u003dutf8\u0026ie\u003dutf8\u0026source\u003duds\u0026start\u003d0\u0026hl\u003den-GB\u0026q\u003dcheese""}}, ""responseDetails"": null, ""responseStatus"": 200}";
g1 = JSONHelper.Deserialise<GoogleSearchResults>(json);
Response.Write(g1.content);
}
}
public class JSONHelper
{
public static T Deserialise<T>(string json)
{
T obj = Activator.CreateInstance<T>();
MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json));
DataContractJsonSerializer serialiser = new DataContractJsonSerializer(obj.GetType());
ms.Close();
return obj;
}
}
/// Deserialise from JSON
[Serializable]
public class GoogleSearchResults
{
public GoogleSearchResults() { }
public GoogleSearchResults(string _unescapedUrl, string _url, string _visibleUrl, string _cacheUrl, string _title, string _titleNoFormatting, string _content)
{
this.unescapedUrl = _unescapedUrl;
this.url = _url;
this.visibleUrl = _visibleUrl;
this.cacheUrl = _cacheUrl;
this.title = _title;
this.titleNoFormatting = _titleNoFormatting;
this.content = _content;
}
string _unescapedUrl;
string _url;
string _visibleUrl;
string _cacheUrl;
string _title;
string _titleNoFormatting;
string _content;
[DataMember]
public string unescapedUrl
{
get { return _unescapedUrl; }
set { _unescapedUrl = value; }
}
[DataMember]
public string url
{
get { return _url; }
set { _url = value; }
}
[DataMember]
public string visibleUrl
{
get { return _visibleUrl; }
set { _visibleUrl = value; }
}
[DataMember]
public string cacheUrl
{
get { return _cacheUrl; }
set { _cacheUrl = value; }
}
[DataMember]
public string title
{
get { return _title; }
set { _title = value; }
}
[DataMember]
public string titleNoFormatting
{
get { return _titleNoFormatting; }
set { _titleNoFormatting = value; }
}
[DataMember]
public string content
{
get { return _content; }
set { _content = value; }
}
}
코드는 현재 컴파일되고 완벽하게 실행되지만 결과를 반환하지 않습니다. 누군가 내가 필요한 것을 반환하고 결과를 화면에 인쇄 할 수 있도록 도와 줄 수 있습니까?
편집하다:
Json.NET은 위 예제와 동일한 JSON 및 클래스를 사용하여 작동합니다.
GoogleSearchResults g1 = JsonConvert.DeserializeObject<GoogleSearchResults>(json);
링크 : Json.NET을 사용하여 JSON 직렬화 및 역 직렬화
관련
JSON 형식의 데이터를 중첩 해시 테이블로
구문 분석 JSON 배열 구문 분석
답변
[업데이트]
방금 결과를받지 못한 이유를 알게되었습니다 … Deserialize
방법에 누락 된 줄이 있습니다 . 결과를 다음에 할당하는 것을 잊었습니다 obj
.
public static T Deserialize<T>(string json)
{
using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json)))
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(T));
return (T)serializer.ReadObject(ms);
}
}
또한 참고 용으로 다음과 같은 Serialize
방법이 있습니다.
public static string Serialize<T>(T obj)
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
using (MemoryStream ms = new MemoryStream())
{
serializer.WriteObject(ms, obj);
return Encoding.Default.GetString(ms.ToArray());
}
}
편집하다
Json.NET을 사용하려면 위 코드와 동일한 Serialize / Deserialize 메소드가 있습니다.
역 직렬화 :
JsonConvert.DeserializeObject<T>(string json);
직렬화 :
JsonConvert.SerializeObject(object o);
이것은 이미 Json.NET의 일부이므로 JsonConvert 클래스에서 호출 할 수 있습니다.
링크 : Json.NET을 사용하여 JSON 직렬화 및 역 직렬화
이제 StackOverflow를 얻는 이유는입니다 Properties
.
예를 들면 다음과 같습니다.
[DataMember]
public string unescapedUrl
{
get { return unescapedUrl; } // <= this line is causing a Stack Overflow
set { this.unescapedUrl = value; }
}
유의 사항에 것을 getter
, 당신은 실제 속성을 반환하는 (즉,이 호텔의 게터는 또 다시 자신을 호출), 따라서 당신은 무한 재귀를 만들 수 있습니다.
속성 (2.0)은 다음과 같이 정의해야합니다.
string _unescapedUrl; // <= private field
[DataMember]
public string unescapedUrl
{
get { return _unescapedUrl; }
set { _unescapedUrl = value; }
}
개인 필드가 있고 getter에서 해당 필드의 값을 리턴하고 setter에서 해당 필드의 값을 설정하십시오.
Btw, 3.5 프레임 워크를 사용하는 경우이 작업을 수행하고 백업 필드를 피하고 컴파일러가 처리하도록 할 수 있습니다.
public string unescapedUrl { get; set;}
답변
데이터 클래스가 JSON 객체와 일치하지 않습니다. 대신 이것을 사용하십시오 :
[DataContract]
public class GoogleSearchResults
{
[DataMember]
public ResponseData responseData { get; set; }
}
[DataContract]
public class ResponseData
{
[DataMember]
public IEnumerable<Results> results { get; set; }
}
[DataContract]
public class Results
{
[DataMember]
public string unescapedUrl { get; set; }
[DataMember]
public string url { get; set; }
[DataMember]
public string visibleUrl { get; set; }
[DataMember]
public string cacheUrl { get; set; }
[DataMember]
public string title { get; set; }
[DataMember]
public string titleNoFormatting { get; set; }
[DataMember]
public string content { get; set; }
}
또한 직렬화 해제를 위해 클래스를 인스턴스화하지 않아도됩니다.
public static T Deserialise<T>(string json)
{
using (var ms = new MemoryStream(Encoding.Unicode.GetBytes(json)))
{
var serialiser = new DataContractJsonSerializer(typeof(T));
return (T)serialiser.ReadObject(ms);
}
}
답변
나는이 방법을 발견 동적 객체로 JSON을 구문 분석을 , 그것은을 확장 DynamicObject
하고 JavascriptConverter
객체에 문자열을 켭니다.
DynamicJsonObject
public class DynamicJsonObject : DynamicObject
{
private IDictionary<string, object> Dictionary { get; set; }
public DynamicJsonObject(IDictionary<string, object> dictionary)
{
this.Dictionary = dictionary;
}
public override bool TryGetMember(GetMemberBinder binder, out object result)
{
result = this.Dictionary[binder.Name];
if (result is IDictionary<string, object>)
{
result = new DynamicJsonObject(result as IDictionary<string, object>);
}
else if (result is ArrayList && (result as ArrayList) is IDictionary<string, object>)
{
result = new List<DynamicJsonObject>((result as ArrayList).ToArray().Select(x => new DynamicJsonObject(x as IDictionary<string, object>)));
}
else if (result is ArrayList)
{
result = new List<object>((result as ArrayList).ToArray());
}
return this.Dictionary.ContainsKey(binder.Name);
}
}
변환기
public class DynamicJsonConverter : JavaScriptConverter
{
public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
{
if (dictionary == null)
throw new ArgumentNullException("dictionary");
if (type == typeof(object))
{
return new DynamicJsonObject(dictionary);
}
return null;
}
public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{
throw new NotImplementedException();
}
public override IEnumerable<Type> SupportedTypes
{
get { return new ReadOnlyCollection<Type>(new List<Type>(new Type[] { typeof(object) })); }
}
}
사용법 ( sample json ) :
JavaScriptSerializer jss = new JavaScriptSerializer();
jss.RegisterConverters(new JavaScriptConverter[] { new DynamicJsonConverter() });
dynamic glossaryEntry = jss.Deserialize(json, typeof(object)) as dynamic;
Console.WriteLine("glossaryEntry.glossary.title: " + glossaryEntry.glossary.title);
Console.WriteLine("glossaryEntry.glossary.GlossDiv.title: " + glossaryEntry.glossary.GlossDiv.title);
Console.WriteLine("glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.ID: " + glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.ID);
Console.WriteLine("glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.para: " + glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.para);
foreach (var also in glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.GlossSeeAlso)
{
Console.WriteLine("glossaryEntry.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.GlossSeeAlso: " + also);
}
이 메소드는 true를 리턴해야합니다. 그렇지 않으면 오류가 발생합니다. 예를 들어 키가 존재하지 않으면 오류가 발생할 수 있습니다.
반환 true
하고 result
비우면 오류가 발생하지 않고 빈 값이 반환됩니다.
public override bool TryGetMember(GetMemberBinder binder, out object result)
{
if (!this.Dictionary.ContainsKey(binder.Name))
{
result = "";
}
else
{
result = this.Dictionary[binder.Name];
}
if (result is IDictionary<string, object>)
{
result = new DynamicJsonObject(result as IDictionary<string, object>);
}
else if (result is ArrayList && (result as ArrayList) is IDictionary<string, object>)
{
result = new List<DynamicJsonObject>((result as ArrayList).ToArray().Select(x => new DynamicJsonObject(x as IDictionary<string, object>)));
}
else if (result is ArrayList)
{
result = new List<object>((result as ArrayList).ToArray());
}
return true; // this.Dictionary.ContainsKey(binder.Name);
}
답변
나는 단지 전체 예가 유용하다고 생각합니다. 이것이이 문제의 예입니다.
using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.ServiceModel.Web;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
using System.IO;
using System.Text;
using System.Collections.Generic;
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
GoogleSearchResults g1 = new GoogleSearchResults();
const string json = @"{""responseData"": {""results"":[{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.cheese.com/"",""url"":""http://www.cheese.com/"",""visibleUrl"":""www.cheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:bkg1gwNt8u4J:www.cheese.com"",""title"":""\u003cb\u003eCHEESE\u003c/b\u003e.COM - All about \u003cb\u003echeese\u003c/b\u003e!."",""titleNoFormatting"":""CHEESE.COM - All about cheese!."",""content"":""\u003cb\u003eCheese\u003c/b\u003e - everything you want to know about it. Search \u003cb\u003echeese\u003c/b\u003e by name, by types of milk, by textures and by countries.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://en.wikipedia.org/wiki/Cheese"",""url"":""http://en.wikipedia.org/wiki/Cheese"",""visibleUrl"":""en.wikipedia.org"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:n9icdgMlCXIJ:en.wikipedia.org"",""title"":""\u003cb\u003eCheese\u003c/b\u003e - Wikipedia, the free encyclopedia"",""titleNoFormatting"":""Cheese - Wikipedia, the free encyclopedia"",""content"":""\u003cb\u003eCheese\u003c/b\u003e is a food consisting of proteins and fat from milk, usually the milk of cows, buffalo, goats, or sheep. It is produced by coagulation of the milk \u003cb\u003e...\u003c/b\u003e""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.ilovecheese.com/"",""url"":""http://www.ilovecheese.com/"",""visibleUrl"":""www.ilovecheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:GBhRR8ytMhQJ:www.ilovecheese.com"",""title"":""I Love \u003cb\u003eCheese\u003c/b\u003e!, Homepage"",""titleNoFormatting"":""I Love Cheese!, Homepage"",""content"":""The American Dairy Association\u0026#39;s official site includes recipes and information on nutrition and storage of \u003cb\u003echeese\u003c/b\u003e.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.gnome.org/projects/cheese/"",""url"":""http://www.gnome.org/projects/cheese/"",""visibleUrl"":""www.gnome.org"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:jvfWnVcSFeQJ:www.gnome.org"",""title"":""\u003cb\u003eCheese\u003c/b\u003e"",""titleNoFormatting"":""Cheese"",""content"":""\u003cb\u003eCheese\u003c/b\u003e uses your webcam to take photos and videos, applies fancy special effects and lets you share the fun with others. It was written as part of Google\u0026#39;s \u003cb\u003e...\u003c/b\u003e""}],""cursor"":{""pages"":[{""start"":""0"",""label"":1},{""start"":""4"",""label"":2},{""start"":""8"",""label"":3},{""start"":""12"",""label"":4},{""start"":""16"",""label"":5},{""start"":""20"",""label"":6},{""start"":""24"",""label"":7},{""start"":""28"",""label"":8}],""estimatedResultCount"":""14400000"",""currentPageIndex"":0,""moreResultsUrl"":""http://www.google.com/search?oe\u003dutf8\u0026ie\u003dutf8\u0026source\u003duds\u0026start\u003d0\u0026hl\u003den-GB\u0026q\u003dcheese""}}, ""responseDetails"": null, ""responseStatus"": 200}";
g1 = JSONHelper.Deserialise<GoogleSearchResults>(json);
foreach (Pages x in g1.responseData.cursor.pages)
{
// Anything you want to get
Response.Write(x.label);
}
}
}
public class JSONHelper
{
public static T Deserialise<T>(string json)
{
using (var ms = new MemoryStream(Encoding.Unicode.GetBytes(json)))
{
var serialiser = new DataContractJsonSerializer(typeof(T));
return (T)serialiser.ReadObject(ms);
}
}
public static string Serialize<T>(T obj)
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
using (MemoryStream ms = new MemoryStream())
{
serializer.WriteObject(ms, obj);
return Encoding.Default.GetString(ms.ToArray());
}
}
}
[DataContract]
public class GoogleSearchResults
{
[DataMember]
public ResponseData responseData { get; set; }
[DataMember]
public string responseStatus { get; set; }
}
public class ResponseData
{
[DataMember]
public Cursor cursor { get; set; }
[DataMember]
public IEnumerable<Results> results { get; set; }
}
[DataContract]
public class Cursor
{
[DataMember]
public IEnumerable<Pages> pages { get; set; }
}
[DataContract]
public class Pages
{
[DataMember]
public string start { get; set; }
[DataMember]
public string label { get; set; }
}
[DataContract]
public class Results
{
[DataMember]
public string unescapedUrl { get; set; }
[DataMember]
public string url { get; set; }
[DataMember]
public string visibleUrl { get; set; }
[DataMember]
public string cacheUrl { get; set; }
[DataMember]
public string title { get; set; }
[DataMember]
public string titleNoFormatting { get; set; }
[DataMember]
public string content { get; set; }
}
답변
위의 코드를 사용하려고했지만 작동하지 않았습니다. Google이 반환하는 JSON 구조는 매우 다르며 도우미 함수 DataContractJsonSerializer.ReadObject()
에는 JSON 데이터를 실제로 개체로 deserialize 하는 호출이 매우 중요 합니다.
2011 년에 작동하는 코드는 다음과 같습니다.
using System;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
using System.IO;
using System.Text;
using System.Collections.Generic;
namespace <YOUR_NAMESPACE>
{
public class JSONHelper
{
public static T Deserialise<T>(string json)
{
T obj = Activator.CreateInstance<T>();
MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json));
DataContractJsonSerializer serialiser = new DataContractJsonSerializer(obj.GetType());
obj = (T)serialiser.ReadObject(ms);
ms.Close();
return obj;
}
}
public class Result
{
public string GsearchResultClass { get; set; }
public string unescapedUrl { get; set; }
public string url { get; set; }
public string visibleUrl { get; set; }
public string cacheUrl { get; set; }
public string title { get; set; }
public string titleNoFormatting { get; set; }
public string content { get; set; }
}
public class Page
{
public string start { get; set; }
public int label { get; set; }
}
public class Cursor
{
public string resultCount { get; set; }
public Page[] pages { get; set; }
public string estimatedResultCount { get; set; }
public int currentPageIndex { get; set; }
public string moreResultsUrl { get; set; }
public string searchResultTime { get; set; }
}
public class ResponseData
{
public Result[] results { get; set; }
public Cursor cursor { get; set; }
}
public class GoogleSearchResults
{
public ResponseData responseData { get; set; }
public object responseDetails { get; set; }
public int responseStatus { get; set; }
}
}
첫 번째 결과의 내용을 얻으려면 다음을 수행하십시오.
GoogleSearchResults googleResults = new GoogleSearchResults();
googleResults = JSONHelper.Deserialise<GoogleSearchResults>(jsonData);
string contentOfFirstResult = googleResults.responseData.results[0].content;
답변
도와 주셔서 감사합니다. 이것은 나의 최종 버전이며, 당신의 결합 된 도움 덕분에 작동합니다! 내가 변경 한 내용 만 표시하고 나머지는 Joe Chung의 작업 에서 가져옵니다.
public class GoogleSearchResults
{
[DataMember]
public ResponseData responseData { get; set; }
[DataMember]
public string responseDetails { get; set; }
[DataMember]
public int responseStatus { get; set; }
}
과
[DataContract]
public class ResponseData
{
[DataMember]
public List<Results> results { get; set; }
}
답변
Google Map API 요청 및 DirectionsResponse를 C #으로 구문 분석하고 URL의 json을 xml로 변경 한 후 다음 코드를 사용하여 결과를 사용 가능한 C # Generic List Object로 변환하십시오.
만드는 데 시간이 걸렸습니다. 그러나 여기 있습니다
var url = String.Format("http://maps.googleapis.com/maps/api/directions/xml?...");
var result = new System.Net.WebClient().DownloadString(url);
var doc = XDocument.Load(new StringReader(result));
var DirectionsResponse = doc.Elements("DirectionsResponse").Select(l => new
{
Status = l.Elements("status").Select(q => q.Value).FirstOrDefault(),
Route = l.Descendants("route").Select(n => new
{
Summary = n.Elements("summary").Select(q => q.Value).FirstOrDefault(),
Leg = n.Elements("leg").ToList().Select(o => new
{
Step = o.Elements("step").Select(p => new
{
Travel_Mode = p.Elements("travel_mode").Select(q => q.Value).FirstOrDefault(),
Start_Location = p.Elements("start_location").Select(q => new
{
Lat = q.Elements("lat").Select(r => r.Value).FirstOrDefault(),
Lng = q.Elements("lng").Select(r => r.Value).FirstOrDefault()
}).FirstOrDefault(),
End_Location = p.Elements("end_location").Select(q => new
{
Lat = q.Elements("lat").Select(r => r.Value).FirstOrDefault(),
Lng = q.Elements("lng").Select(r => r.Value).FirstOrDefault()
}).FirstOrDefault(),
Polyline = p.Elements("polyline").Select(q => new
{
Points = q.Elements("points").Select(r => r.Value).FirstOrDefault()
}).FirstOrDefault(),
Duration = p.Elements("duration").Select(q => new
{
Value = q.Elements("value").Select(r => r.Value).FirstOrDefault(),
Text = q.Elements("text").Select(r => r.Value).FirstOrDefault(),
}).FirstOrDefault(),
Html_Instructions = p.Elements("html_instructions").Select(q => q.Value).FirstOrDefault(),
Distance = p.Elements("distance").Select(q => new
{
Value = q.Elements("value").Select(r => r.Value).FirstOrDefault(),
Text = q.Elements("text").Select(r => r.Value).FirstOrDefault(),
}).FirstOrDefault()
}).ToList(),
Duration = o.Elements("duration").Select(p => new
{
Value = p.Elements("value").Select(q => q.Value).FirstOrDefault(),
Text = p.Elements("text").Select(q => q.Value).FirstOrDefault()
}).FirstOrDefault(),
Distance = o.Elements("distance").Select(p => new
{
Value = p.Elements("value").Select(q => q.Value).FirstOrDefault(),
Text = p.Elements("text").Select(q => q.Value).FirstOrDefault()
}).FirstOrDefault(),
Start_Location = o.Elements("start_location").Select(p => new
{
Lat = p.Elements("lat").Select(q => q.Value).FirstOrDefault(),
Lng = p.Elements("lng").Select(q => q.Value).FirstOrDefault()
}).FirstOrDefault(),
End_Location = o.Elements("end_location").Select(p => new
{
Lat = p.Elements("lat").Select(q => q.Value).FirstOrDefault(),
Lng = p.Elements("lng").Select(q => q.Value).FirstOrDefault()
}).FirstOrDefault(),
Start_Address = o.Elements("start_address").Select(q => q.Value).FirstOrDefault(),
End_Address = o.Elements("end_address").Select(q => q.Value).FirstOrDefault()
}).ToList(),
Copyrights = n.Elements("copyrights").Select(q => q.Value).FirstOrDefault(),
Overview_polyline = n.Elements("overview_polyline").Select(q => new
{
Points = q.Elements("points").Select(r => r.Value).FirstOrDefault()
}).FirstOrDefault(),
Waypoint_Index = n.Elements("waypoint_index").Select(o => o.Value).ToList(),
Bounds = n.Elements("bounds").Select(q => new
{
SouthWest = q.Elements("southwest").Select(r => new
{
Lat = r.Elements("lat").Select(s => s.Value).FirstOrDefault(),
Lng = r.Elements("lng").Select(s => s.Value).FirstOrDefault()
}).FirstOrDefault(),
NorthEast = q.Elements("northeast").Select(r => new
{
Lat = r.Elements("lat").Select(s => s.Value).FirstOrDefault(),
Lng = r.Elements("lng").Select(s => s.Value).FirstOrDefault()
}).FirstOrDefault(),
}).FirstOrDefault()
}).FirstOrDefault()
}).FirstOrDefault();
이것이 누군가를 도울 수 있기를 바랍니다.