어드민

ContextLoaderListener이다 선택 . 그냥 여기에 포인트로 만들려면 : 혹시 구성하지 않고 Spring 애플리케이션을 부팅 할 수 있습니다 ContextLoaderListener, 단지 기본 최소 web.xml로를 DispatcherServlet.

다음과 같은 모습입니다.

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="
        http://java.sun.com/xml/ns/javaee
        http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID"
    version="2.5">
  <display-name>Some Minimal Webapp</display-name>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>

  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>
      org.springframework.web.servlet.DispatcherServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>*.do</url-pattern>
  </servlet-mapping>
</web-app>

라는 파일을 작성하고 dispatcher-servlet.xml아래에 저장하십시오 WEB-INF. index.jsp환영 목록에서 언급 했으므로이 파일을 아래에 추가하십시오 WEB-INF.

dispatcher-servlet.xml

에서 dispatcher-servlet.xml당신의 bean을 정의 :

<?xml version="1.0" encoding="UTF-8"?>
<beans
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context.xsd">

    <bean id="bean1">
      ...
    </bean>
    <bean id="bean2">
      ...
    </bean>

    <context:component-scan base-package="com.example" />
    <!-- Import your other configuration files too -->
    <import resource="other-configs.xml"/>
    <import resource="some-other-config.xml"/>

    <!-- View Resolver -->
    <bean
        id="viewResolver"
        class="org.springframework.web.servlet.view.UrlBasedViewResolver">
      <property
          name="viewClass"
          value="org.springframework.web.servlet.view.JstlView" />
      <property name="prefix" value="/WEB-INF/jsp/" />
      <property name="suffix" value=".jsp" />
    </bean>
</beans>

답변

<servlet>
    <servlet-name>hello</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring/mvc-core-config.xml, classpath:spring/business-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:spring/common-config.xml</param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
    <servlet-name>mvc1</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring/mvc1-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet>
    <servlet-name>mvc2</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring/mvc2-config.xmll</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>