상대적으로 간단하다고 생각되는 작업을 수행하려고합니다. Android SDK를 사용하여 이미지를 서버에 업로드합니다. 많은 예제 코드를 찾았습니다.
http://linklens.blogspot.com/2009/06/android-multipart-upload.html
하지만 나에게는 효과가 없습니다. 내가 계속해서 부딪 치는 혼란은 멀티 파트 요청을하기 위해 정말로 필요한 것입니다. Android 용 멀티 파트 업로드 (이미지 포함)를 하는 가장 간단한 방법 은 무엇입니까 ?
어떤 도움이나 조언이라도 대단히 감사하겠습니다!
답변
2014 년 4 월 29 일 업데이트 :
내 대답은 지금은 다소 오래되었으며 Retrofit 과 같은 일종의 고급 라이브러리를 사용하고 싶을 것 같습니다 .
이 블로그를 기반으로 다음과 같은 솔루션을 찾았 습니다.
http://blog.tacticalnuclearstrike.com/2010/01/using-multipartentity-in-android-applications/
MultipartEntity
실행 하려면 추가 라이브러리를 다운로드해야 합니다!
1) http://james.apache.org/download.cgi#Apache_Mime4J 에서 httpcomponents-client-4.1.zip을 다운로드 하고 apache-mime4j-0.6.1.jar를 프로젝트에 추가합니다.
2) http://hc.apache.org/downloads.cgi 에서 httpcomponents-client-4.1-bin.zip을 다운로드 하고 httpclient-4.1.jar, httpcore-4.1.jar 및 httpmime-4.1.jar을 프로젝트에 추가합니다.
3) 아래 예제 코드를 사용하십시오.
private DefaultHttpClient mHttpClient;
public ServerCommunication() {
HttpParams params = new BasicHttpParams();
params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);
mHttpClient = new DefaultHttpClient(params);
}
public void uploadUserPhoto(File image) {
try {
HttpPost httppost = new HttpPost("some url");
MultipartEntity multipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
multipartEntity.addPart("Title", new StringBody("Title"));
multipartEntity.addPart("Nick", new StringBody("Nick"));
multipartEntity.addPart("Email", new StringBody("Email"));
multipartEntity.addPart("Description", new StringBody(Settings.SHARE.TEXT));
multipartEntity.addPart("Image", new FileBody(image));
httppost.setEntity(multipartEntity);
mHttpClient.execute(httppost, new PhotoUploadResponseHandler());
} catch (Exception e) {
Log.e(ServerCommunication.class.getName(), e.getLocalizedMessage(), e);
}
}
private class PhotoUploadResponseHandler implements ResponseHandler<Object> {
@Override
public Object handleResponse(HttpResponse response)
throws ClientProtocolException, IOException {
HttpEntity r_entity = response.getEntity();
String responseString = EntityUtils.toString(r_entity);
Log.d("UPLOAD", responseString);
return null;
}
}
답변
로가 MultiPartEntity
있다 되지 . 그래서 여기에 새로운 방법이 있습니다! 그리고 Apache 사이트 에서만 필요 httpcore.jar(latest)
하고 httpmime.jar(latest)
다운로드 할 수 있습니다.
try
{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(URL);
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
entityBuilder.addTextBody(USER_ID, userId);
entityBuilder.addTextBody(NAME, name);
entityBuilder.addTextBody(TYPE, type);
entityBuilder.addTextBody(COMMENT, comment);
entityBuilder.addTextBody(LATITUDE, String.valueOf(User.Latitude));
entityBuilder.addTextBody(LONGITUDE, String.valueOf(User.Longitude));
if(file != null)
{
entityBuilder.addBinaryBody(IMAGE, file);
}
HttpEntity entity = entityBuilder.build();
post.setEntity(entity);
HttpResponse response = client.execute(post);
HttpEntity httpEntity = response.getEntity();
result = EntityUtils.toString(httpEntity);
Log.v("result", result);
}
catch(Exception e)
{
e.printStackTrace();
}
답변
다음은 외부 HTTPCore 및 이러한 라이브러리없이 저에게 도움이되는 경량 솔루션입니다. 64K 메서드 문제에 직면했기 때문에 HTTPCore 라이브러리를 피할 수있는 옵션이 없습니다.
import java.util.List;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import java.util.ArrayList;
import java.util.List;
/**
* This utility class provides an abstraction layer for sending multipart HTTP
* POST requests to a web server.
*
* @author www.codejava.net
*/
public class MultipartUtility {
private final String boundary;
private static final String LINE_FEED = "\r\n";
private HttpURLConnection httpConn;
private String charset;
private OutputStream outputStream;
private PrintWriter writer;
/**
* This constructor initializes a new HTTP POST request with content type
* is set to multipart/form-data
*
* @param requestURL
* @param charset
* @throws IOException
*/
public MultipartUtility(String requestURL, String charset)
throws IOException {
this.charset = charset;
// creates a unique boundary based on time stamp
boundary = "===" + System.currentTimeMillis() + "===";
URL url = new URL(requestURL);
httpConn = (HttpURLConnection) url.openConnection();
httpConn.setUseCaches(false);
httpConn.setDoOutput(true); // indicates POST method
httpConn.setDoInput(true);
httpConn.setRequestProperty("Content-Type",
"multipart/form-data; boundary=" + boundary);
httpConn.setRequestProperty("User-Agent", "CodeJava Agent");
httpConn.setRequestProperty("Test", "Bonjour");
outputStream = httpConn.getOutputStream();
writer = new PrintWriter(new OutputStreamWriter(outputStream, charset),
true);
}
/**
* Adds a form field to the request
*
* @param name field name
* @param value field value
*/
public void addFormField(String name, String value) {
writer.append("--" + boundary).append(LINE_FEED);
writer.append("Content-Disposition: form-data; name=\"" + name + "\"")
.append(LINE_FEED);
writer.append("Content-Type: text/plain; charset=" + charset).append(
LINE_FEED);
writer.append(LINE_FEED);
writer.append(value).append(LINE_FEED);
writer.flush();
}
/**
* Adds a upload file section to the request
*
* @param fieldName name attribute in <input type="file" name="..." />
* @param uploadFile a File to be uploaded
* @throws IOException
*/
public void addFilePart(String fieldName, File uploadFile)
throws IOException {
String fileName = uploadFile.getName();
writer.append("--" + boundary).append(LINE_FEED);
writer.append(
"Content-Disposition: form-data; name=\"" + fieldName
+ "\"; filename=\"" + fileName + "\"")
.append(LINE_FEED);
writer.append(
"Content-Type: "
+ URLConnection.guessContentTypeFromName(fileName))
.append(LINE_FEED);
writer.append("Content-Transfer-Encoding: binary").append(LINE_FEED);
writer.append(LINE_FEED);
writer.flush();
FileInputStream inputStream = new FileInputStream(uploadFile);
byte[] buffer = new byte[4096];
int bytesRead = -1;
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
outputStream.flush();
inputStream.close();
writer.append(LINE_FEED);
writer.flush();
}
/**
* Adds a header field to the request.
*
* @param name - name of the header field
* @param value - value of the header field
*/
public void addHeaderField(String name, String value) {
writer.append(name + ": " + value).append(LINE_FEED);
writer.flush();
}
/**
* Completes the request and receives response from the server.
*
* @return a list of Strings as response in case the server returned
* status OK, otherwise an exception is thrown.
* @throws IOException
*/
public List<String> finish() throws IOException {
List<String> response = new ArrayList<String>();
writer.append(LINE_FEED).flush();
writer.append("--" + boundary + "--").append(LINE_FEED);
writer.close();
// checks server's status code first
int status = httpConn.getResponseCode();
if (status == HttpURLConnection.HTTP_OK) {
BufferedReader reader = new BufferedReader(new InputStreamReader(
httpConn.getInputStream()));
String line = null;
while ((line = reader.readLine()) != null) {
response.add(line);
}
reader.close();
httpConn.disconnect();
} else {
throw new IOException("Server returned non-OK status: " + status);
}
return response;
}
}
용법
private void uploadMedia() {
try {
String charset = "UTF-8";
File uploadFile1 = new File("/sdcard/myvideo.mp4");
String requestURL = Data.BASE_URL+Data.URL_UPLOAD_REACTION_TEST;
MultipartUtility multipart = new MultipartUtility(requestURL, charset);
// multipart.addHeaderField("User-Agent", "CodeJava");
// multipart.addHeaderField("Test-Header", "Header-Value");
multipart.addFormField("friend_id", "Cool Pictures");
multipart.addFormField("userid", "Java,upload,Spring");
multipart.addFilePart("uploadedfile", uploadFile1);
List<String> response = multipart.finish();
Log.v("rht", "SERVER REPLIED:");
for (String line : response) {
Log.v("rht", "Line : "+line);
}
} catch (Exception e) {
e.printStackTrace();
}
}
업로드를 허용하는 PHP 코드
<?php
$friend_id = $_REQUEST['friend_id'];
$userid = $_REQUEST['userid'];
echo 'friend_id : '.$friend_id. ' userid '.$userid;
move_uploaded_file($_FILES['uploadedfile']['tmp_name'], "./uploads/".$_FILES["uploadedfile"]["name"]);
?>
답변
답변
이 시도:
public void SendMultipartFile() {
Log.d(TAG, "UPLOAD: SendMultipartFile");
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost( <url> );
File file = new File("/sdcard/spider.jpg");
Log.d(TAG, "UPLOAD: setting up multipart entity");
MultipartEntity mpEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
Log.d(TAG, "UPLOAD: file length = " + file.length());
Log.d(TAG, "UPLOAD: file exist = " + file.exists());
try {
mpEntity.addPart("datafile", new FileBody(file, "application/octet"));
mpEntity.addPart("id", new StringBody("1"));
} catch (UnsupportedEncodingException e1) {
Log.d(TAG, "UPLOAD: UnsupportedEncodingException");
e1.printStackTrace();
}
httppost.setEntity(mpEntity);
Log.d(TAG, "UPLOAD: executing request: " + httppost.getRequestLine());
Log.d(TAG, "UPLOAD: request: " + httppost.getEntity().getContentType().toString());
HttpResponse response;
try {
Log.d(TAG, "UPLOAD: about to execute");
response = httpclient.execute(httppost);
Log.d(TAG, "UPLOAD: executed");
HttpEntity resEntity = response.getEntity();
Log.d(TAG, "UPLOAD: respose code: " + response.getStatusLine().toString());
if (resEntity != null) {
Log.d(TAG, "UPLOAD: " + EntityUtils.toString(resEntity));
}
if (resEntity != null) {
resEntity.consumeContent();
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
답변
Loopj를 강력히 추천합니다.
여러 MIME 유형을 포함하여 한 번에 여러 파일을 업로드하는 데 성공적으로 사용했습니다. 다음과 같이하십시오.
File myVideo = new File("/path/to/myvideo.mp4");
File myPic = new File("/path/to/mypic.jpg");
RequestParams params = new RequestParams();
try {
params.put("profile_picture", myPic);
params.put("my_video", myVideo);
} catch(FileNotFoundException e) {}
크거나 많은 파일의 경우 시간 초과 양을 늘려야 할 수 있습니다. 그렇지 않으면 너무 짧을 수있는 기본 시간 초과가 사용됩니다.
client.setTimeout(500000) //make this the appropriate timeout in milliseconds
loopj에 대한 전체 설명과 사용 방법에 대해서는이 링크를 참조하십시오. 내가 본 가장 쉬운 비동기 http 라이브러리입니다.
http://loopj.com/android-async-http/
http://loopj.com/android-async-http/doc/com/loopj/android/http/AsyncHttpClient.html
답변
모든 httpclient, httpmime 종속성을 제거하고이 종속성을 추가하십시오 compile 'commons-httpclient:commons-httpclient:3.1'
. 이 종속성은 MultipartRequestEntity에 내장되어 있으므로 하나 이상의 파일을 서버에 쉽게 업로드 할 수 있습니다.
public class FileUploadUrlConnection extends AsyncTask<String, String, String> {
private Context context;
private String url;
private List<File> files;
public FileUploadUrlConnection(Context context, String url, List<File> files) {
this.context = context;
this.url = url;
this.files = files;
}
@Override
protected String doInBackground(String... params) {
HttpClient client = new HttpClient();
PostMethod post = new PostMethod(url);
HttpClientParams connectionParams = new HttpClientParams();
post.setRequestHeader(// Your header goes here );
try {
Part[] parts = new Part[files.size()];
for (int i=0; i<files.size(); i++) {
Part part = new FilePart(files.get(i).getName(), files.get(i));
parts[i] = part;
}
MultipartRequestEntity entity = new MultipartRequestEntity(parts, connectionParams);
post.setRequestEntity(entity);
int statusCode = client.executeMethod(post);
String response = post.getResponseBodyAsString();
Log.v("Multipart "," "+response);
if(statusCode == 200) {
return response;
}
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
요청 및 응답 시간 제한을 추가 할 수도 있습니다.
client.getParams().setParameter(CoreConnectionPNames.CONNECTION_TIMEOUT, 10000);
client.getParams().setParameter(CoreConnectionPNames.SO_TIMEOUT, 10000);