[python] Python에서 datetime.time에 N 초를 추가하는 표준 방법은 무엇입니까?

datetime.timePython 에 값이 주어지면 정수 초를 추가하는 표준 방법이 있습니까? 예를 들어 11:34:59+ 3 = 11:35:02입니까?

이 명백한 아이디어는 효과가 없습니다.

>>> datetime.time(11, 34, 59) + 3
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'int'
>>> datetime.time(11, 34, 59) + datetime.timedelta(0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
>>> datetime.time(11, 34, 59) + datetime.time(0, 0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.time'

결국 나는 다음과 같은 기능을 작성했다.

def add_secs_to_time(timeval, secs_to_add):
    secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
    secs += secs_to_add
    return datetime.time(secs // 3600, (secs % 3600) // 60, secs % 60)

그래도 더 쉬운 방법이 없다고 생각하면 도움이되지 않습니다.

관련

• python time + timedelta equivalent

답변

import datetime
a = datetime.datetime(100,1,1,11,34,59)
b = a + datetime.timedelta(0,3) # days, seconds, then other fields.
print(a.time())
print(b.time())

11:34:59
11:35:02

b = a + datetime.timedelta(seconds=3)

import datetime

def addSecs(tm, secs):
    fulldate = datetime.datetime(100, 1, 1, tm.hour, tm.minute, tm.second)
    fulldate = fulldate + datetime.timedelta(seconds=secs)
    return fulldate.time()

a = datetime.datetime.now().time()
b = addSecs(a, 300)
print(a)
print(b)

 09:11:55.775695
 09:16:55

from datetime import datetime, date, time, timedelta
sometime = time(8,00) # 8am
later = (datetime.combine(date.today(), sometime) + timedelta(seconds=3)).time()

>>> b = a + datetime.timedelta(seconds=3000)
>>> b
datetime.datetime(1, 1, 1, 12, 24, 59)

def add_secs_to_time(timeval, secs_to_add):
    dummy_date = datetime.date(1, 1, 1)
    full_datetime = datetime.datetime.combine(dummy_date, timeval)
    added_datetime = full_datetime + datetime.timedelta(seconds=secs_to_add)
    return added_datetime.time()

(datetime.datetime.combine(datetime.date(1, 1, 1), timeval) + datetime.timedelta(seconds=secs_to_add)).time()

>>> import datetime
>>> import nptime
>>> nptime.nptime(11, 34, 59) + datetime.timedelta(0, 3)
nptime(11, 35, 2)

>>> from datetime import datetime, timedelta
>>> t = datetime.now() + timedelta(seconds=3000)
>>> print(t)
datetime.datetime(2018, 1, 17, 21, 47, 13, 90244)

sometime = arrow.now()
abitlater = sometime.shift(seconds=3)