[ios] UITapGestureRecognizer-단일 탭 및 이중 탭

UITapGestureRecognizers뷰 에 2를 추가하려고합니다 . 하나는 단일 탭이고 다른 하나는 더블 탭 이벤트입니다. 단일 탭 인식기가 예상대로 작동합니다 (자체적으로). 그러나 더블 탭 인식기가 작동하지 않는 것 같습니다.

유무과 같은 특성을 실험을 시도 : cancelsTouchesInView, delaysTouchesBegan그리고 delaysTouchesEnded하지만 여전히 작동하지 않습니다.

두 번 탭하면 싱글 탭 인식기가 항상 활성화되고 더블 탭 이벤트도 슈퍼 뷰로 전송됩니다. 그러나 사용자 정의 더블 탭 인식기는 전혀 알리지 않는 것 같습니다.

문서는 위에서 언급 한 3 가지 속성을 목적으로 사용할 수 있다고 제안합니다. 그러나 어떤 값을 설정해야하며 어떤 인식기 (싱글, 더블 또는 둘 다)인지 확실하지 않습니다. 이것에 익숙한 누군가가 도움이되기를 바랍니다.

다음은 최신 업데이트 코드 블록입니다.

// ****** gesture recognizers ******

- (void)addSingleAndDoubleTapGestureRecognizersToView:(UIView *)view
{
    // single tap    
    UITapGestureRecognizer *singleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector(handleSingleTapOnView:)];
    [singleTapRecognizer setNumberOfTouchesRequired:1];
    [view addGestureRecognizer: singleTapRecognizer];

    // double tap 
    UITapGestureRecognizer *doubleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector (handleDoubleTapOnView:)];
    [doubleTapRecognizer setNumberOfTouchesRequired:2];
    [singleTapRecognizer requireGestureRecognizerToFail: doubleTapRecognizer];
    [view addGestureRecognizer: doubleTapRecognizer];
}

- (void)handleSingleTapOnView:(id)sender
{

}

- (void)handleDoubleTapOnView:(id)sender
{

}



답변

UITapGestureRecognizer *singleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doSingleTap)] autorelease];
singleTap.numberOfTapsRequired = 1;
[self.view addGestureRecognizer:singleTap];

UITapGestureRecognizer *doubleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doDoubleTap)] autorelease];
doubleTap.numberOfTapsRequired = 2;
[self.view addGestureRecognizer:doubleTap];

[singleTap requireGestureRecognizerToFail:doubleTap];

참고 : 당신이 사용하는 경우 numberOfTouchesRequired 가되어야한다 .numberOfTouchesRequired = 1;

스위프트

let singleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didPressPartButton))
singleTapGesture.numberOfTapsRequired = 1
view.addGestureRecognizer(singleTapGesture)

let doubleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didDoubleTap))
doubleTapGesture.numberOfTapsRequired = 2
view.addGestureRecognizer(doubleTapGesture)

singleTapGesture.require(toFail: doubleTapGesture)


답변

스위프트 3 솔루션 :

let singleTap = UITapGestureRecognizer(target: self, action:#selector(self.singleTapAction(_:)))
singleTap.numberOfTapsRequired = 1
view.addGestureRecognizer(singleTap)

let doubleTap = UITapGestureRecognizer(target: self, action:#selector(self.doubleTapAction(_:)))
doubleTap.numberOfTapsRequired = 2
view.addGestureRecognizer(doubleTap)

singleTap.require(toFail: doubleTap)

코드 라인 singleTap.require (toFail : doubleTap)에서 우리는 싱글 탭을 기다리게하고 탭 이벤트가 더블 탭이 아닌지 확인합니다.


답변

requireGestureRecognizerToFail : 메소드를 사용해야합니다. 이 같은:

[singleTapRecognizer requireGestureRecognizerToFail:doubleTapRecognizer];


답변

// —- 먼저 더블 및 싱글 탭 제스처를 할당해야합니다 .——– //

UITapGestureRecognizer* doubleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleDoubleTap:)];

UITapGestureRecognizer* singleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleSingleTap:)];

[singleTap requireGestureRecognizerToFail : doubleTap];
[doubleTap setDelaysTouchesBegan : YES];
[singleTap setDelaysTouchesBegan : YES];

// ———————– 탭수 —————- //

[doubleTap setNumberOfTapsRequired : 2];
[singleTap setNumberOfTapsRequired : 1];

// ——-보기 또는 버튼에 더블 탭 및 싱글 탭 제스처 추가 ——– //

[self.view addGestureRecognizer : doubleTap];
[self.view addGestureRecognizer : singleTap];


답변

그것이 정확히 당신이 찾고있는 것인지 확실하지 않지만 제스처 인식기가없는 싱글 / 더블 탭을했습니다. UITableView에서 사용하고 있으므로 didSelectRowAtIndexPath 메서드에서 해당 코드를 사용했습니다.

    tapCount++;
    switch (tapCount)
    {
        case 1: //single tap
            [self performSelector:@selector(singleTap:) withObject: indexPath afterDelay: 0.2];
            break;
        case 2: //double tap
            [NSObject cancelPreviousPerformRequestsWithTarget:self selector:@selector(singleTap:) object:indexPath];
            [self performSelector:@selector(doubleTap:) withObject: indexPath];
            break;
        default:
            break;
    }
    if (tapCount>2) tapCount=0;

singleTap 및 doubleTap 메소드는 NSIndexPath를 매개 변수로 사용하여 void입니다.

- (void)singleTap:(NSIndexPath *)indexPath {
  //do your stuff for a single tap
}

- (void)doubleTap:(NSIndexPath *)indexPath {
  //do your stuff for a double tap
}

그것이 도움이되기를 바랍니다.


답변

스위프트 2 솔루션 :

let singleTapGesture = UITapGestureRecognizer(target: self, action: #selector(handleSingleTap))
singleTapGesture.numberOfTapsRequired = 1 // Optional for single tap
view.addGestureRecognizer(singleTapGesture)

let doubleTapGesture = UITapGestureRecognizer(target: self, action: #selector(handleDoubleTap))
doubleTapGesture.numberOfTapsRequired = 2
view.addGestureRecognizer(doubleTapGesture)

singleTapGesture.requireGestureRecognizerToFail(doubleTapGesture)


답변

singleTap과 doubleTap을 모두 감지하기 위해 UIGestureRecognizerDelegate 메소드를 구현했습니다.

그냥하세요.

 UITapGestureRecognizer *doubleTap = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handleDoubleTapGesture:)];
    [doubleTap setDelegate:self];
    doubleTap.numberOfTapsRequired = 2;
    [self.headerView addGestureRecognizer:doubleTap];

    UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handleSingleTapGesture:)];
    singleTap.numberOfTapsRequired = 1;
    [singleTap setDelegate:self];
    [doubleTap setDelaysTouchesBegan:YES];
    [singleTap setDelaysTouchesBegan:YES];
    [singleTap requireGestureRecognizerToFail:doubleTap];
    [self.headerView addGestureRecognizer:singleTap];

그런 다음 이러한 대리자 메서드를 구현하십시오.

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch{
    return  YES;
}

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer{
    return YES;
}