[objective-c] Objective-C로 JSON을 어떻게 구문 분석합니까?

Program / 글쓴이

저는 iPhone을 처음 사용합니다. 누구든지이 데이터를 구문 분석하고 활동 세부 정보, 이름 및 성을 얻기 위해 따라야 할 단계를 알려줄 수 있습니까?

{
    "#error": false,
    "#data": {
        "": {
            "activity_id": "35336",
            "user_id": "1",
            "user_first_name": "Chandra Bhusan",
            "user_last_name": "Pandey",
            "time": "1300870420",
            "activity_details": "Good\n",
            "activity_type": "status_update",
            "photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-1627435117.jpg"
        },
        "boolean": "1",
        "1": {
            "1": {
                "photo_1_id": "9755"
            },
            "activity_id": "35294",
            "album_name": "Kalai_new_Gallery",
            "user_id": "31",
            "album_id": "9754",
            "user_first_name": "Kalaiyarasan",
            "user_last_name": "Balu",
            "0": {
                "photo_0_id": "9756"
            },
            "time": "1300365758",
            "activity_type": "photo_upload",
            "photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/"
        },
        "3": {
            "activity_id": "35289",
            "user_id": "33",
            "user_first_name": "Girija",
            "user_last_name": "S",
            "time": "1300279636",
            "activity_details": "girija Again\n",
            "activity_type": "status_update",
            "photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg"
        },
        "2": {
            "owner_first_name": "Girija",
            "activity_id": "35290",
            "activity_details": "a:2:{s:4:\"html\";s:51:\"!user_fullname and !friend_fullname are now friends\";s:4:\"type\";s:10:\"friend_add\";}",
            "activity_type": "friend accept",
            "owner_last_name": "S",
            "time": "1300280400",
            "photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg",
            "owner_id": "33"
        },
        "4": {
            "activity_id": "35288",
            "user_id": "33",
            "user_first_name": "Girija",
            "user_last_name": "S",
            "time": "1300279530",
            "activity_details": "girija from mobile\n",
            "activity_type": "status_update",
            "photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg"
        }
    }
}

답변

OS X v10.7 및 iOS 5 출시의 관점에서 볼 때 지금 가장 먼저 권장 할 것은 NSJSONSerialization Apple에서 제공 한 JSON 파서 일 것입니다. 런타임에 해당 클래스를 사용할 수없는 경우에만 타사 옵션을 대체 옵션으로 사용하십시오.

예를 들면 다음과 같습니다.

NSData *returnedData = ...JSON data, probably from a web request...

// probably check here that returnedData isn't nil; attempting
// NSJSONSerialization with nil data raises an exception, and who
// knows how your third-party library intends to react?

if(NSClassFromString(@"NSJSONSerialization"))
{
    NSError *error = nil;
    id object = [NSJSONSerialization
                      JSONObjectWithData:returnedData
                      options:0
                      error:&error];

    if(error) { /* JSON was malformed, act appropriately here */ }

    // the originating poster wants to deal with dictionaries;
    // assuming you do too then something like this is the first
    // validation step:
    if([object isKindOfClass:[NSDictionary class]])
    {
        NSDictionary *results = object;
        /* proceed with results as you like; the assignment to
        an explicit NSDictionary * is artificial step to get
        compile-time checking from here on down (and better autocompletion
        when editing). You could have just made object an NSDictionary *
        in the first place but stylistically you might prefer to keep
        the question of type open until it's confirmed */
    }
    else
    {
        /* there's no guarantee that the outermost object in a JSON
        packet will be a dictionary; if we get here then it wasn't,
        so 'object' shouldn't be treated as an NSDictionary; probably
        you need to report a suitable error condition */
    }
}
else
{
    // the user is using iOS 4; we'll need to use a third-party solution.
    // If you don't intend to support iOS 4 then get rid of this entire
    // conditional and just jump straight to
    // NSError *error = nil;
    // [NSJSONSerialization JSONObjectWithData:...
}

답변

바퀴를 재발 명하지 마십시오. json-framework 또는 유사한 것을 사용하십시오 .

json-framework를 사용하기로 결정한 경우 JSON 문자열을 다음과 같이 구문 분석하는 방법은 NSDictionary다음과 같습니다.

SBJsonParser* parser = [[[SBJsonParser alloc] init] autorelease];
// assuming jsonString is your JSON string...
NSDictionary* myDict = [parser objectWithString:jsonString];

// now you can grab data out of the dictionary using objectForKey or another dictionary method

답변

NSString* path  = [[NSBundle mainBundle] pathForResource:@"index" ofType:@"json"];

//将文件内容读取到字符串中，注意编码NSUTF8StringEncoding 防止乱码，
NSString* jsonString = [[NSString alloc] initWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];

//将字符串写到缓冲区。
NSData* jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];

NSError *jsonError;
id allKeys = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONWritingPrettyPrinted error:&jsonError];


for (int i=0; i<[allKeys count]; i++) {
    NSDictionary *arrayResult = [allKeys objectAtIndex:i];
    NSLog(@"name=%@",[arrayResult objectForKey:@"storyboardName"]);

}

파일:

 [
  {
  "ID":1,
  "idSort" : 0,
  "deleted":0,
  "storyboardName" : "MLMember",
  "dispalyTitle" : "76.360779",
  "rightLevel" : "10.010490",
  "showTabBar" : 1,
  "openWeb" : 0,
  "webUrl":""
  },
  {
  "ID":1,
  "idSort" : 0,
  "deleted":0,
  "storyboardName" : "0.00",
  "dispalyTitle" : "76.360779",
  "rightLevel" : "10.010490",
  "showTabBar" : 1,
  "openWeb" : 0,
  "webUrl":""
  }
  ]

답변

NSJSONSerialization을 사용한 JSON 구문 분석

   NSString* path  = [[NSBundle mainBundle] pathForResource:@"data" ofType:@"json"];

    //Here you can take JSON string from your URL ,I am using json file
    NSString* jsonString = [[NSString alloc] initWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];
    NSData* jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
    NSError *jsonError;
    NSArray *jsonDataArray = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:kNilOptions error:&jsonError];

    NSLog(@"jsonDataArray: %@",jsonDataArray);

    NSDictionary *jsonObject = [NSJSONSerialization JSONObjectWithData:jsonData options:kNilOptions error:&jsonError];
if(jsonObject !=nil){
   // NSString *errorCode=[NSMutableString stringWithFormat:@"%@",[jsonObject objectForKey:@"response"]];


        if(![[jsonObject objectForKey:@"#data"] isEqual:@""]){

            NSMutableArray *array=[jsonObject objectForKey:@"#data"];
             // NSLog(@"array: %@",array);
            NSLog(@"array: %d",array.count);

            int k = 0;
            for(int z = 0; z<array.count;z++){

                NSString *strfd = [NSString stringWithFormat:@"%d",k];
                NSDictionary *dicr = jsonObject[@"#data"][strfd];
                k=k+1;
                // NSLog(@"dicr: %@",dicr);
                 NSLog(@"Firstname - Lastname   : %@ - %@",
                     [NSMutableString stringWithFormat:@"%@",[dicr objectForKey:@"user_first_name"]],
                     [NSMutableString stringWithFormat:@"%@",[dicr objectForKey:@"user_last_name"]]);
            }

          }

     }

다음과 같이 콘솔 출력을 볼 수 있습니다.

이름-성 : Chandra Bhusan-Pandey

이름-성 : Kalaiyarasan-Balu

이름-성 : (null)-(null)

이름-성 : Girija-S

이름-성 : Girija-S

이름-성 : (null)-(null)

답변

  1. JSON 구문 분석을 위해 TouchJSON 을 권장하고 사용 합니다.

  2. Alex에게 귀하의 의견에 답하기 위해. 반환 된 json 사전에서 activity_details, last_name 등과 같은 필드를 가져올 수있는 빠른 코드는 다음과 같습니다.

    NSDictionary *userinfo=[jsondic valueforKey:@"#data"];
NSDictionary *user;
NSInteger i = 0;
NSString *skey;
if(userinfo != nil){
    for( i = 0; i < [userinfo count]; i++ ) {
        if(i)
            skey = [NSString stringWithFormat:@"%d",i];
        else
            skey = @"";

        user = [userinfo objectForKey:skey];
        NSLog(@"activity_details:%@",[user objectForKey:@"activity_details"]);
        NSLog(@"last_name:%@",[user objectForKey:@"last_name"]);
        NSLog(@"first_name:%@",[user objectForKey:@"first_name"]);
        NSLog(@"photo_url:%@",[user objectForKey:@"photo_url"]);
    }
}

답변